Bracket Checking
Question:-
Write a function matched(s) that takes as input a string s and checks if the brackets "(" and ")" in s are matched: that is, every "(" has a matching ")" after it and every ")" has a matching "(" before it. Your function should ignore all other symbols that appear in s. Your function should return True if s has matched brackets and False if it does not.
Here are some examples to show how your function should work.
>>> matched("zb%78")
True
>>> matched("(7)(a")False>>> matched("a)*(?")False>>> matched("((jkl)78(A)&l(8(dd(FJI:),):)?)")True
Solution:-
Write a function matched(s) that takes as input a string s and checks if the brackets "(" and ")" in s are matched: that is, every "(" has a matching ")" after it and every ")" has a matching "(" before it. Your function should ignore all other symbols that appear in s. Your function should return True if s has matched brackets and False if it does not.
Here are some examples to show how your function should work.
>>> matched("zb%78")
True
>>> matched("(7)(a")False>>> matched("a)*(?")False>>> matched("((jkl)78(A)&l(8(dd(FJI:),):)?)")True
Solution:-
def matched(s): a = 0 for i in range(0, len(s)): if s[i] == '(': if a >= 0: a = a + 1 elif s[i] == ')': a = a - 1 if a == 0: return True else : return False
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